Posted by Raj on Saturday, November 13, 2010 at 4:51pm.
f(x) = √(2x)
f '(x) = (/2)(2)(2x)^(-1/2) or 1/√(2x)
f(2) = 2
f'(2) = 1/2
tangent equation:
x - 2y = c
at (2,2)
2-4=c
c = -2
tanglent: x-2y=-2
normal: slope = -2
equation:
2x + y = k
at (2,2,)
4+2 = k = 6
normal : 2x + y = 6
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