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October 24, 2014

October 24, 2014

Posted by **kwaku** on Saturday, November 13, 2010 at 12:40pm.

- physics -
**drwls**, Saturday, November 13, 2010 at 12:50pmLet the tension be T and the angle of the string to the horizontal be A.

Write equations for horizontal and vertical motion.

T sin A = M g

T cos A = M V^2/r

Square both sides and add the two equations to get T

T^2(sin^2A + cos^2A) = T

= M^2(g + V^2/r)

Solve for T.

You need to know the length of the wire (r) to solve this problem. They should have told you what it is.

- physics -
**Ann**, Monday, December 13, 2010 at 2:42pmA person places the speakers 4.0 m apart and connects a signal generator to both speakers that produces a single and consistent tone. (constant wavelength and frequency) He then walks to a point that is 2.0 m from one speaker and 2.3 m from the other. At that point he notices a quiet “spot”. If the speed of the sound in the room is known to be 350 m/s, calculate the possible frequencies being played by the speakers.

My Answer:

PD=2.3m-2m

PD=.3m

PD=(n-.5) λ, but λ=v/f

PD=(n-.5)(v/f)

.3=(n-.5)(350/f)

f=(n-.5)(350/.3)

f=(n-.5)(3500/3)

f=(3500n/3)-(3500/6)

f=(3500n/3)-(3500/6), where n is any real integer.

Is this right? Thanks for your help.

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