Posted by andrea on Saturday, November 13, 2010 at 5:30am.
Calculate the kinetic energy increase and divide it by 0.4, to account for the inefficiency.
(1/2)M*V^2/0.4
= 6.5*10^5 Joules
That is the fuel energy burned. 60% of that goes to heating the engine, if the engine is 40% efficient.
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