Posted by stan on Friday, November 12, 2010 at 9:36pm.
(1) The ball reaches its highest point when g*t = 23.7 m/s, because that is where the vertical velocity component becomes zero.
t = 23.7/g = 23.7/9.8 = 2.4 seconds. It matters not what height the ball is thrown from, for this part.
(2) The highest point will be at a distance
Vo*t - (g/2)t^2 = 28.7 m above where it was thrown from. That will be 30.7 m above the ground.
Now all you have to do is compute the new time required to fall that distance. Call it t'
Use 30.7 m = (g/2)*t'^2 and solve for t'.
Related Questions
physics - A ball is thrown vertically upward with a speed of 26.8 m/s from a ...
phy - A blue ball is thrown upward with an initial speed of 20.6 m/s, from a ...
Physics please help!!!!!!! - A ball is thrown vertically upward (assumed to be ...
Physics - A ball is thrown vertically upward with a speed of 25.4 m/s from a ...
Physics - A red ball is thrown down with an initial speed of 1.3 m/s from a ...
physics - A red ball is thrown down with an initial speed of 1.2 m/s from a ...
physics - A ball is thrown vertically upward with a speed of 24.7 m/s from a ...
physics - A ball is thrown vertically upward with a speed of 24.7 m/s from a ...
physics - A ball is thrown vertically upward with an initial speed of 20 m/s. ...
Physics - A ball is thrown vertically upward with a speed of 26.1 m/s from a ...
For Further Reading
