Posted by **stan** on Friday, November 12, 2010 at 9:36pm.

A ball is thrown vertically upward with a

speed of 23.7 m/s from a height of 2.0 m.

How long does it take to reach its high-

est point? The acceleration of gravity is

9.81 m/s2

2) How long does the ball take to hit the ground after it reaches its highest point?

- physics -
**drwls**, Saturday, November 13, 2010 at 6:53am
(1) The ball reaches its highest point when g*t = 23.7 m/s, because that is where the vertical velocity component becomes zero.

t = 23.7/g = 23.7/9.8 = 2.4 seconds. It matters not what height the ball is thrown from, for this part.

(2) The highest point will be at a distance

Vo*t - (g/2)t^2 = 28.7 m above where it was thrown from. That will be 30.7 m above the ground.

Now all you have to do is compute the new time required to fall that distance. Call it t'

Use 30.7 m = (g/2)*t'^2 and solve for t'.

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