March 27, 2015

Homework Help: Calculus

Posted by Sara on Friday, November 12, 2010 at 7:11pm.

I'm having a little trouble with this would be great if you could point out where I'm going wrong.
Hours of Daylight as a Function of Latitude.
Let S(x) be the number of sunlight hours on a cloudless June 21st, as a function of latitude, x, measured in degrees.
a.) What is S(0)?
(b) Let x0 be the latitude of the Arctic Circle. In the northern hemisphere, S (x)
is given, for some constants a and b, by the formula:
S (x) = bracket (piecewise function)
a + b arcsin*(tan x/tan x0)
for 0 ≤ x < x0
24 for x0 ≤ x ≤ 90.
Find a and b so that S (x) is continuous.
(c) Calculate S (x) for Tucson, Arizona (x = 32◦ 13′ ) and Walla Walla, Washington (46◦ 4′ ).
(d) Graph S (x), for 0 ≤ x ≤ 90.
(e) Does S (x) appear to be differentiable?

My answers:
a.) @ 0 degrees latitude, you're at the equator, so S(0) = 12 hours daylight
b.) Since S(0)=12,
12 = a + b arcsin * (tan0/tan x0)
12 = a + b arcsin 0
12 = a + b0
12 = a,

and for b, because the function must be continuous,
24 = 12 + b arcsin* (tan 66/tan 66)
12 = b arcsin* 1
7.639 (rounded) = b.

But now when I try to find the answer to part C,
latitude of Tucson= 32 degrees
S(x)= 12 + 7.639 arcsin* (tan 32/tan 66)

...I get a nonreal answer for the arcsin of (tan 32/tan 66).

Can anyone please tell me where I'm going wrong? Thanks!

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