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July 28, 2014

July 28, 2014

Posted by **tonda** on Friday, November 12, 2010 at 6:28pm.

- math -
**Henry**, Saturday, November 13, 2010 at 4:49pmX = hor = 40 mi/h * 1 h + 40 mi/h * 0.5 h * cos45 = 40 + 14.1 = 54.1 mi.

Y = ver = 40 mi/h * 0.5 h * sin45 = 14.1 mi.

tanA = Y/X = 14.1 / 54.1 = 0.2606,

A = 14.6 deg.

d = x / cosA = 54,1 / cos14.6= 55.9 mi.

from starting position.

8

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