posted by autumn on .
once a 21 kg crate is in motion on a hoizontal floor, a horizontal force of 58 N keeps the crate moving with a constant velocity.
the acceleration of gravity is 9.81 m/s^2. what is mu k , the coefficient of kinetic friction, between the crate and the floor?
The friction force equals the applied force (58N) in this no-acceleration case. They are in opposite directions, and cancel out.
58 = M*g*muk
Solve for muk