How many pi bonds and sigma bonds are in ritalin molecule?

I counted 4 pi bonds and 18 sigma bonds is that correct? I know double bonds are pi bonds and single bonds are pi bonds

Agreed, 4 pi bonds and 18 sigma bonds.

To determine the number of pi (π) and sigma (σ) bonds in a molecule like Ritalin, first, we need to analyze its structure. Ritalin, also known as methylphenidate, has a molecular formula of C14H19NO2.

To identify sigma bonds, we focus on all the single bonds in the molecule. In Ritalin, there are 18 sigma bonds since each single bond represents one sigma bond.

Next, let's determine the number of pi bonds. Pi bonds are present in double bonds, triple bonds, and aromatic rings. In Ritalin, there are no aromatic rings, so we only need to consider double bonds.

Upon examining the structure of Ritalin, we observe that there is only one double bond present, between the carbon and oxygen atoms in the carbonyl group (C=O). This bond represents one pi bond.

Therefore, you correctly identified that Ritalin has 18 sigma bonds. However, there is only 1 pi bond, not 4 as you mentioned.