Posted by **Cornelius** on Thursday, November 11, 2010 at 9:19pm.

*62. A 40.0-kg boy, riding a 2.50-kg skateboard at a velocity of +5.30 m/s across a level sidewalk, jumps forward to leap over a wall. Just after leaving contact with the board, the boy's velocity relative to the sidewalk is 6.00 m/s, 9.50° above the horizontal. Ignore any friction between the skateboard and the sidewalk. What is the skateboard's velocity relative to the sidewalk at this instant? Be sure to include the correct algebraic sign with your answer.

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**drwls**, Thursday, November 11, 2010 at 9:45pm
Your question contains its own answer.

"..the boy's velocity relative to the sidewalk is 6.00 m/s, 9.50° above the horizontal."

The components of the velocity are:

6.00 cos9.5 = 5.92 m/s horizontal and

6.00 sin9.5 = 0.99 m/s vertical

- Physics -
**Anonymous**, Wednesday, March 14, 2012 at 10:25pm
(6-5.5)cos(7.3)

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**Anonymous**, Thursday, May 29, 2014 at 4:42pm
Two diamonds begin a free fall from rest from the same height, a time ?t (delta t) apart. How long after the first diamond begins to fall will the two diamonds be a distance d apart? Give your answer in terms of the variables given and g. Must be given in variables.. this is a symbolic problem

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