Posted by **gen** on Thursday, November 11, 2010 at 8:01pm.

if y1=x^2+3x-1 and y2=x-5,

find: a. y1+y2

b. y1-y2

c. y1(y2)

- calculus -
**jai**, Thursday, November 11, 2010 at 8:38pm
y1 = x^2 + 3x - 1

y2 = x - 5

for y1 - y2, combine similar terms,, for terms with same variables, add their numerical coefficients (number before the variable) and copy the variable:

x^2 + 3x - 1 -(x - 5)

x^2 + 3x - 1 - x + 5

x^2 + 3x - x - 1 + 5 *i just rearrange the terms*

x^2 + 2x + 4

for y1(y2), distribute each term:

(x^2 + 3x - 1)(x - 5)

to distribute, multiply x^2 by x plus x^2 times -5, plus 3x times x plus 3x times -5, and so on:

(x^2)*x + (-5)x^2 + 3x^2 - 15x - x + 5

now simplify this by combining similar terms.

- calculus -
**Anon**, Thursday, November 11, 2010 at 8:41pm
Alright. a. y1+y2 should be set up as follows:

(x^2+3x-1)+(x-5), which equates to

x^2+4x-6

You just combine the like terms.

b. (x^2+3x-1)-(x-5)

For this one you need to distribute the negative, to get x^2+3x-1-x+5, then combine like terms.

c. (x-5)(x^2+3x-1)= x^3+3x^2-x-5x^2-15x+5. Combine like terms.

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