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calculus

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if y1=x^2+3x-1 and y2=x-5,
find: a. y1+y2
b. y1-y2
c. y1(y2)

  • calculus -

    y1 = x^2 + 3x - 1
    y2 = x - 5
    for y1 - y2, combine similar terms,, for terms with same variables, add their numerical coefficients (number before the variable) and copy the variable:
    x^2 + 3x - 1 -(x - 5)
    x^2 + 3x - 1 - x + 5
    x^2 + 3x - x - 1 + 5 *i just rearrange the terms*
    x^2 + 2x + 4

    for y1(y2), distribute each term:
    (x^2 + 3x - 1)(x - 5)
    to distribute, multiply x^2 by x plus x^2 times -5, plus 3x times x plus 3x times -5, and so on:
    (x^2)*x + (-5)x^2 + 3x^2 - 15x - x + 5
    now simplify this by combining similar terms.

  • calculus -

    Alright. a. y1+y2 should be set up as follows:
    (x^2+3x-1)+(x-5), which equates to
    x^2+4x-6
    You just combine the like terms.

    b. (x^2+3x-1)-(x-5)
    For this one you need to distribute the negative, to get x^2+3x-1-x+5, then combine like terms.

    c. (x-5)(x^2+3x-1)= x^3+3x^2-x-5x^2-15x+5. Combine like terms.

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