Posted by tarkan on Thursday, November 11, 2010 at 5:40pm.
There is a shorter way of doing this but I like the long way.
Convert moles each to the product, then take the smaller product amount as coming from the limiting reagent.
2 moles N2 x (2 moles NH3/2 moles N2) = 2 moles NH3.(The fractions comes from the coefficients.)
5 moles H2 x (2 moles NH3/3 moles H2) = 3.33 moles NH3.
The smaller number is N2, that is the limiting reagent.
The others are done the same way. For excess reagent, use the limiting reagent, convert to the excess reagent with the appropriate fraction to determine how much is used in the reaction, subtract that from the moles initially there to determine the amount that did not react.
hey can u show me the shorter way to do plzzz and thx for the answer... :)
See your other post.
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