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Homework Help: chemistry

Posted by flame on Thursday, November 11, 2010 at 4:03pm.

if 0.4M NaOH is titrated with 0.4M HF, how do we calcualte the ph at equivalence. The book assumes each is 1L, but why do we use 1L

* chemistry - Dr.Jim, Thursday, November 11, 2010 at 5:31am

HF is a weak acid, so you need the dissociation constant. The pH at the equivalence point is found by calculating the pH of a 0.4M NaF solution (a hydrolysis problem). If you erroneously assume that HF is a strong acid, then the answer is simple. The pH at the equivalence point is 7.

how can a weak acid and strong base titration has ph=7 at equivalence. It's only when they are both strong acid and base

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