Posted by bobjahng2 on Thursday, November 11, 2010 at 12:56am.
well, what you know
Vertical
hf=ho+vi*t-4.9t^2
135=0+VsinTheta*t-4.9t^2
Horizontal:
195=VcosTheta*t
Ok, t=6.5 so
VcosTheta= 195/6.5
in the vertical equation, solving for VsinTheta=(135+4.9*6.5^2)/6.5
then tanTheta= Vsintheta/VcosTheta, so figure out theta.
then go back knowing theta and figure V.
check my work, I did it in my head.
Related Questions
physics - A projectile is launched from ground level to the top of a cliff which...
Physics - A projectile is launched from ground level to the top of a cliff which...
physics - A projectile is launched from ground level to the top of a cliff which...
Physics - A projectile is launched from ground level to the top of a cliff which...
Physics - A projectile is launched from ground level to the top of a cliff which...
math - A projectile is launched from ground level to the top of a cliff which is...
physics - projectile is launched horizontally from edge of cliff 20 m high with ...
Physics -.- - A projectile is shot horizontally at 220 m/s from the top of a 620...
physics - A projectile is launched off of a 18.6 m high cliff with a velocity ...
Physics - A projectile is fired from ground level with a speed of 40 m/s at an ...
For Further Reading