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Posted by on Thursday, November 11, 2010 at 12:56am.

A projectile is launched from ground level to the top of a cliff which is 195 m away and 135 m high.If the projectile lands on top of the cliff 6.5 s after it is fired, find the initial velocity of the projectile ( (a)magnitude and (b)direction ). Neglect air resistance.

  • physics - , Thursday, November 11, 2010 at 9:29am

    well, what you know
    Vertical
    hf=ho+vi*t-4.9t^2
    135=0+VsinTheta*t-4.9t^2

    Horizontal:
    195=VcosTheta*t

    Ok, t=6.5 so
    VcosTheta= 195/6.5

    in the vertical equation, solving for VsinTheta=(135+4.9*6.5^2)/6.5

    then tanTheta= Vsintheta/VcosTheta, so figure out theta.

    then go back knowing theta and figure V.

    check my work, I did it in my head.

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