Posted by Daniel on Wednesday, November 10, 2010 at 11:54pm.
Let V be the balloon volume.
Let rho1 = air density and
rho2 = helium density. Look them up or use the gas law to compute them. Helium weighs 4/29 as much as air at the same T and p.
For the balloon and its weight to be lifted,
rho1*V = 4000 + 600 + rho2*V
V = 4600/(rho1-rho2)
ok what is rho? I know the answer to this problem is 9.96 m because our teacher gave us the answer
Ok nvm i will do the math. Sorry didnt read what they stood for. Thx for the help =)
Related Questions
Physics - A 600-kg weather ballon is designed to lift a 4000-kg package. What ...
physics - A 650 kg weather balloon is designed to lift a 4600 kg package. What ...
calculus - a splenical ballon is being inflated @ 10 cubic inches per secound. ...
Calculus - a spherical ballon is being inflated at a constant rate of 25 cm^3/...
chemistry - A weather ballon with a 2 meter diameter at ambient temperature ...
math - This one is kinda hard. "A ballon in the shape of a cylinder with ...
calculus - This one is tough. "A ballon in the shape of a cylinder with ...
Physics - A weather ballon is designed to expand to a maximum radius of 20 m at ...
Physics - A weather ballon is designed to expand to a maximum radius of 20 m at ...
physical science - imagine that you added helium gas to a partially inflated ...
For Further Reading
