Homework Help: physics...again :/

Posted by clueless on Wednesday, November 10, 2010 at 10:00pm.

A skier starts from rest at the top of a hill that is inclined at 9.9° with the horizontal. The hillside is 160 m long, and the coefficient of friction between snow and skis is 0.0750. At the bottom of the hill, the snow is level and the coefficient of friction is unchanged. How far does the skier move along the horizontal portion of the snow before coming to rest?

physics...again :/ - bobpursley, Wednesday, November 10, 2010 at 10:03pm
the potential energy the skier had, mg*160Sin9.9 is all converted to heat in friction.
PE= friction on slide+frictiononhorizontal
mg*160sin9.9= mu*mg*Sin9.9*160 + mu*mg*distance.

solve for distance.

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