posted by clueless on .
A skier starts from rest at the top of a hill that is inclined at 9.9° with the horizontal. The hillside is 160 m long, and the coefficient of friction between snow and skis is 0.0750. At the bottom of the hill, the snow is level and the coefficient of friction is unchanged. How far does the skier move along the horizontal portion of the snow before coming to rest?
the potential energy the skier had, mg*160Sin9.9 is all converted to heat in friction.
PE= friction on slide+frictiononhorizontal
mg*160sin9.9= mu*mg*Sin9.9*160 + mu*mg*distance.
solve for distance.