-8=1/3x+x
-8 = 1/(3x) + x ?
you notation is confusing, could be
-8 = 1/(3x+x)
or even
-8 = (1/3) x + x
but I will do the first first
-24x = 1 + 3 x^2
3 x^2 + 24 x - 1 = 0
solve using quadratic equation
x = [-24 +/- sqrt(576 + 12) ] / 6
x = [-24 +/- 24.25 ] /6
x = 1/24 or - 8
I figured it out.
-8=1/3x+x
-8*3=1/3x*3+x
-24=3x+x
-24=4x
-24/4+4x/4
-6=x
-8=1/3*-6+-6
-8=-6/3-6
-8=-2-6
-8=-8
To find the value of x in the equation -8 = (1/3)x + x, we will combine like terms and then solve for x.
First, we need to combine the x terms on the right side of the equation. To do this, we add (1/3)x and x:
-8 = (1/3)x + x
To add (1/3)x and x, we need to have a common denominator. The least common denominator between 3 and 1 is 3. So, we need to convert the x term to have a denominator of 3:
-8 = (1/3)x + (3/3)x
Simplifying this expression, we have:
-8 = (1/3 + 3/3)x
Combining the fractions in the parentheses, we get:
-8 = (4/3)x
Now, we want to isolate x on one side of the equation. To do this, we need to undo the multiplication of (4/3) by x. We can do this by multiplying both sides of the equation by the reciprocal of (4/3), which is (3/4):
(-8)(3/4) = [(4/3)x][(3/4)]
Simplifying this further, we have:
-6 = x
Hence, the value of x in the equation -8 = (1/3)x + x is x = -6.