Posted by clueless on Wednesday, November 10, 2010 at 8:25pm.
Starting from rest, a 10.2 kg block slides 2.90 m down a frictionless ramp (inclined at 30.0° from the floor) to the bottom. The block then slides an additional 4.80 m along the floor before coming to a stop. Determine the coefficient of kinetic friction between block and floor.

ap physics  bobpursley, Wednesday, November 10, 2010 at 8:32pm
ap?
the block has mgh of PE when it starts, so at the bottom all that energy is kinetic.
Now, friction absorbs this energy, so
mu*mg*distance=mgh
solve for mu
Notice the distance is independent of mass. Neat experiment to show this.

ap physics  Damon, Wednesday, November 10, 2010 at 8:33pm
distance down = 2.9 sin 30 = 1.45 meter
Ke at bottom = U at top = m g h = m*g*1.45 Joules
Work done by friction = that KE
mu m g * 4.8
so
m*g*1.45 = mu m g *4.8
mu = 1.45/4.8
note m g cancels

ap physics  Walter White, Thursday, March 5, 2015 at 10:22am
I am the one who nocks just put that in
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