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Posted by on Wednesday, November 10, 2010 at 8:25pm.

Starting from rest, a 10.2 kg block slides 2.90 m down a frictionless ramp (inclined at 30.0° from the floor) to the bottom. The block then slides an additional 4.80 m along the floor before coming to a stop. Determine the coefficient of kinetic friction between block and floor.

  • ap physics - , Wednesday, November 10, 2010 at 8:32pm

    the block has mgh of PE when it starts, so at the bottom all that energy is kinetic.
    Now, friction absorbs this energy, so

    solve for mu
    Notice the distance is independent of mass. Neat experiment to show this.

  • ap physics - , Wednesday, November 10, 2010 at 8:33pm

    distance down = 2.9 sin 30 = 1.45 meter

    Ke at bottom = U at top = m g h = m*g*1.45 Joules

    Work done by friction = that KE
    mu m g * 4.8
    m*g*1.45 = mu m g *4.8

    mu = 1.45/4.8

    note m g cancels

  • ap physics - , Thursday, March 5, 2015 at 10:22am

    I am the one who nocks just put that in

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