Posted by Elizabeth on Wednesday, November 10, 2010 at 4:51pm.
Need answer tomorrow for pre-lab Thanks
Use the Henderson-Hasselbalch equation.
pH = pKa + log (base/acid)
pKb = 4.70; therefore, pKa = 14.0-4.70 = 9.3
Solve two equations simultaneously.
Plug in 9.0 for pH and solve for (B/A) and I get 0.501 which you should confirm. If B/A = 0.501 then
(Base) = 0.501*(acid)
The second equation is
(base) + (acid) = 0.05
Solve for base and acid. I get something like
(acid) = 0.0333 M
(base) = 0.0167 M
We have two solutions, both 0.1 M with which to make this. Use a dilution process (formula) to determine how much of each should be taken.
0.1M x (x Liters/0.25 L) = 0.0333 M.
Solve for x = 0.08325 L or 83.25 mL acid.
0.1 M x (x liters/0.25) = 0.0167 M
Solve for x = 0.04175 L or 41.75 mL base.
Therefore, the instructions would be to measure 83.25 mL of NH4Cl and 41.75 mL NH3, place in a 250 mL volumetric flask and make to the mark with water. But you shouldn't stop there. You should go through and prove four things.
1. The final solution is 250 mL.
2. The final solution is 0.05 M.
3. The final (acid) is 0.0333 (or whatever value you find above) and the final (base) = 0.0167 (or whatever value you find above.)
4. The final pH is 9.0.
Thanks!
Related Questions
Chemistry - A buffer solution of pH=9.24 can be prepared by dissolving ammonia ...
Chemistry - A buffer is prepared by mixng 150.0 mL of 0.500 M ammonia, 250.0 mL ...
Chemistry - Q1: You wish to prepare a buffer solution with pH = 11.10. What ...
Chemistry - Q1: You wish to prepare a buffer solution with pH = 11.10. What ...
chem buffer - When the following solutions are mixed, which will act as a ...
chemistry - To 160.0 mL of a buffer solution containing 0.250 M ammonia and 0....
Chemistry - In the study of biochemical processes, a common buffering agent is ...
Chemistry - Assignment  Calculate the pH, pOH, [H+], and [OH&#...
chemistry - Choices: True,False. Select all that are True. The pH at the ...
Chemistry - PartA: What volume of 10.0M NaOH is needed to prepare a buffer with ...
For Further Reading
