For each reaction, complete and balance the equation and give the net ionic equation.

a) KOH(aq)+ZnCl2(aq)-> KCl2+ZnOH

The second half of the equation is how i had done on the exam but he said its not balanced. How do I balance this? How would it look. I keep trying but not getting. I would appreciate it if you could do this question so I can use as a guide for other similar questions.

Your problem is you don't have the correct formula for zinc hydroxide. It should be Zn(OH)2.

2KOH(aq) + ZnCl2(aq) ==> 2KCl(aq) + Zn(OH)2(s)

You can put in the aq (and s) on the total ionic equation but here it is.
2K^+ + 2OH^- + Zn^+2 + 2Cl^- ==>2K^+ + 2Cl^- + Zn(OH)2
Now cancel the ions common to both sides; i.e., 2K^+ appears on both sides and 2Cl^- appears on both sides. Get rid of them and you are left with
2OH^-(aq) + Zn^+2(aq) ==> Zn(OH)2(s) which is the net ionic equation.

To balance the chemical equation:

a) KOH(aq) + ZnCl2(aq) -> KCl2 + ZnOH

1. Begin by counting the number of atoms of each element on both sides of the equation:
Left side: 1 K, 1 O, 1 H, 1 Zn, 2 Cl
Right side: 1 K, 2 Cl, 1 Zn, 1 O, 1 H

2. Start by balancing the elements that appear in only one reactant and one product. In this case, only K appears in both sides, so there is no need to balance it.

3. Balance the next most complex polyatomic ion, which is OH. There is one OH on the left side and one OH on the right side, so OH is already balanced.

4. Now, let's balance Cl. There are 2 Cl on the left side and only 1 Cl on the right side. Therefore, we need to place a coefficient of 2 in front of KCl on the right side to balance the Cl atoms.

5. Check the balance of all other atoms. After adding the coefficient, the equation looks like this:

KOH(aq) + ZnCl2(aq) -> 2 KCl + ZnOH

Now, all the atoms are balanced.

To write the net ionic equation, we remove the spectator ions, which are the ions that do not undergo any chemical change. In this case, the spectator ions are K+ and Cl-. The net ionic equation is:

Zn2+(aq) + 2 OH-(aq) -> Zn(OH)2(s)

To balance the given chemical equation:

a) KOH(aq) + ZnCl2(aq) -> KCl2 + ZnOH

First, let's balance the potassium (K) atoms by placing a coefficient of 2 in front of KOH:

2KOH(aq) + ZnCl2(aq) -> KCl2 + ZnOH

Next, let's balance the chlorine (Cl) atoms by placing a coefficient of 2 in front of ZnCl2:

2KOH(aq) + 2ZnCl2(aq) -> KCl2 + ZnOH

Now, let's balance the hydroxide (OH) and zinc (Zn) atoms. It seems there is an error in the given equation as KCl2 and ZnOH do not represent valid chemical formulas. However, based on the reactants used, we can assume that KCl2 is meant to represent 2KCl and ZnOH is meant to represent Zn(OH)2. We will balance the equation with these assumptions:

2KOH(aq) + 2ZnCl2(aq) -> 2KCl + Zn(OH)2

Now that the equation is balanced, we can write the net ionic equation by representing all soluble ionic compounds as ions:

2K+(aq) + 2OH-(aq) + 2Zn2+(aq) + 4Cl-(aq) -> 2K+(aq) + 2Cl-(aq) + Zn(OH)2(s)

In the net ionic equation, we remove spectator ions (ions that appear on both sides of the equation) and only include the ions involved in the actual chemical reaction. In this case, the spectator ions are 2K+ and 2Cl-, leaving us with the final net ionic equation:

2OH-(aq) + 2Zn2+(aq) -> Zn(OH)2(s)