Homework Help: Chemistry

Posted by Tokey on Wednesday, November 10, 2010 at 2:31am.

The standard free energy of activation of one reaction is 94.3 kj/mol^-1 (22.54 kcal/mol^-1). The standard free energy of activation for another reaction is 76.4 kJ/mol^-1 (18.26 kcal/mol^-1). Assume temp of 298K and 1 M conc. By what factor is one faster than the other?

Im not sure if this is right but do you subtract the lower kcal value from the other and then multiply by 10? Thanks!

No one has answered this question yet.

Answer this Question

Related Questions

Chemistry - The standard free energy of activation of a reaction A is 88.6 kJ ...
chemistry - The standard free energy of activation of a reaction A is 78.2 kJ ...
chemistry - The activation energy for the reaction in which CO2 decomposes to CO...
chemistry - I have two questions that I really don't understand. The first ...
Physics - The activation energy for the isomerization ol cyclopropane to propene...
Chemistry - For a one step reaction, the activation energy for the forward ...
chemistry - For a one step reaction, the activation energy for the forward ...
chemistry - For a one step reaction, the activation energy for the forward ...
chemistry - For a one step reaction, the activation energy for the forward ...
Chemistry - A reaction has a standard free-energy change of –12.40 kJ mol&#...

For Further Reading

First Name:
School Subject:
Answer: