Tuesday

October 21, 2014

October 21, 2014

Posted by **REALLY NEED HELP!!!!** on Wednesday, November 10, 2010 at 1:05am.

I got... f'(x)=4(x^2 - cos[x]) and f(x)=(4(x^3 - 3sin[x]))/3 but it's wrong. Can anyone explain to me how to solve this.

- Math: Calculus -
**Reiny**, Wednesday, November 10, 2010 at 8:26amy '' = 8x + 4sin(x)

y ' 4x^2 - 4cosx + C

f'(0) = 2 --- > 2 = 0 - 4(cos0) + C

2 = 0-4 + C

C = 6

so y' = 4x^2 - 4cosx + 6

y = (4/3)x^3 - 4sinx + 6x + K

f(0) = 2 ---> 2 = 0 - 4sin0 + 0 + K

K = 2

then y = (4/3)x^3 - 4sinx + 6x + 2

check by differentiating and subbing in x = 0 at each level

**Answer this Question**

**Related Questions**

Calculus Please Need Urgent2 :/ - Consider the function f(x) whose second ...

Calculus2 - Consider the function f(x) whose second derivative is f''(x)=8x+4sin...

Calculus - Consider the function f(x) whose second derivative is f''(x)=5x+2sin(...

calculus - Consider the function whose second derivative is f''(x)=7x+6sin(x). ...

calculus - Consider the function f(x) whose second derivative is f(x)=9x+6sin(x...

Math - Consider the function f(x) whose second derivative is f(x)=10x+2sin(x). ...

math - Consider the function f(x) whose second derivative is f''(x) = 5 x + 6 \...

calculus - Find the derivative of the function 1)f(t)=tan(e^2t)+e^tan2t f'(t)= [...

CALCULUS HELP - Find the second derivative for the function 5x^3+60x^2-36x-41 ...

Calculus - Decide if the following function f(x) is differentiable at x=0. Try ...