given that the molecular weight of mg(oh)2, magnesium hydrogen, is 58-32g, what percentage of this compound is oxygen?

What is mg(oh)2? What is 58-32g? And I have no idea what magnesium hydrogen is.

Yes, very badly written question. If you want the help, the questions need to make sense.

If I assume that the question is asking for the percentage (by mass) of O in
Mg(OH)2 then

mass of O in 1 mole of compound is 2x16 g=32 g

molar mass of compound is (24.3+32+2) g = 58.3 g

so percentage of O by mass is

32 g x100%/58.3 g

To determine the percentage of oxygen in the compound Mg(OH)2 (magnesium hydroxide), we need to calculate the molar mass of the compound and then determine the percentage of oxygen by mass.

The molar mass of Mg(OH)2 can be calculated by adding up the atomic masses of all its constituent elements.

Molar mass of magnesium (Mg) = 24.31 g/mol
Molar mass of oxygen (O) = 16.00 g/mol
Molar mass of hydrogen (H) = 1.01 g/mol

So, the molar mass of Mg(OH)2 is:
(24.31 g/mol x 1) + (16.00 g/mol x 2) + (1.01 g/mol x 2) = 58.33 g/mol

Therefore, the molar mass of Mg(OH)2 is approximately 58.33 g/mol.

To find the percentage of oxygen in the compound, we need to divide the molar mass of oxygen by the molar mass of Mg(OH)2 and multiply by 100.

Percentage of oxygen in Mg(OH)2 = (16.00 g/mol x 2) / 58.33 g/mol x 100%
= 32.00 g/mol / 58.33 g/mol x 100%
≈ 54.9%

Therefore, oxygen makes up approximately 54.9% (rounded to one decimal place) of the compound Mg(OH)2.

To calculate the percentage of oxygen in a compound, we need to have the molar mass of the compound.

In this case, you have mentioned that the molecular weight of Mg(OH)2 (magnesium hydroxide) is 58-32g. I assume that you meant 58 + 32g, since the molar mass of Mg(OH)2 is actually 58.3g/mol.

Now, let's break down the compound into its constituent elements: magnesium (Mg), oxygen (O), and hydrogen (H).

The molar mass of magnesium (Mg) is approximately 24.3g/mol, the molar mass of oxygen (O) is approximately 16.0g/mol, and the molar mass of hydrogen (H) is approximately 1.0g/mol.

In one molecule of Mg(OH)2, there are 2 oxygen atoms, so the contribution of oxygen to the total molar mass can be calculated as follows:

(2 oxygen atoms) * (16.0g/mol) = 32.0g

Therefore, out of the total molar mass of 58.3g/mol for Mg(OH)2, 32.0g can be attributed to oxygen.

To find the percentage of oxygen in the compound, we can use the following formula:

Percentage of oxygen = (Mass of oxygen / Total molar mass) * 100

Percentage of oxygen = (32.0g / 58.3g) * 100 ≈ 55%

So, approximately 55% of the compound Mg(OH)2 is made up of oxygen.