physics
posted by Adam on .
A boulder with a mass of 2,500 kg on a ledge 200 m above the ground falls. If the boulder's mechanical energy is conserved, what is the speed of the boulder just before it hits the ground?

1/2 m vf^2=m*g*height
solve for vf
notice mass divides out.
vf=sqrt(2gh) 
How do you figure miles per hour?

what do you mean, Adam?

I meant meters per second