Homework Help: Chemistry

Posted by Angie on Tuesday, November 9, 2010 at 4:40pm.

How much vinegar at 5% acetic acid concentration would be required to neutralize 100mL of 0.01 M NaOH? (Assume a density of vinegar to be 1.01g/mL)

Chemistry - DrBob222, Tuesday, November 9, 2010 at 5:20pm
What is the molarity of the vinegar solution? 5% means 5 g acetic acid/100 g solution. 5 g acetic acid is ?? moles?
moles = grams/molar mass
100 g is how many mL?
Use density.
Then molarity = M = mols/L soln.

After you know the molarity of 5% acetic acid, then mL x M = mL x M.

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