posted by Angie on .
How much vinegar at 5% acetic acid concentration would be required to neutralize 100mL of 0.01 M NaOH? (Assume a density of vinegar to be 1.01g/mL)
What is the molarity of the vinegar solution? 5% means 5 g acetic acid/100 g solution. 5 g acetic acid is ?? moles?
moles = grams/molar mass
100 g is how many mL?
Then molarity = M = mols/L soln.
After you know the molarity of 5% acetic acid, then mL x M = mL x M.