Saturday

December 20, 2014

December 20, 2014

Posted by **Student42** on Tuesday, November 9, 2010 at 2:05pm.

g = (G*M)/(r^2)

where M is the mass of the Earth, r is the distance from the center of the Earth, and G is the uniform gravitational constant.

(a) Suppose that we change from our distance from the center of the Earth by a distance \Delta r = x. Use a linear approximation to find an approximation to the resulting change in g, as a fraction of the original acceleration:

(Your answer will be a function of x and r.)

(b) Is this change positive or negative?

(c) What is the percentage change in g when moving from sea level to the top of Mount Elbert (a mountain over 14,000 feet tall in Colorado; in km, its height is 4.29 km; assume the radius of the Earth is 6400 km)?

percent change =

- calculus -
**steven**, Wednesday, October 24, 2012 at 2:44ama) -2(x/r)

b) Negative

c) 2(4.29 / 6400) * 100

**Answer this Question**

**Related Questions**

Physics - A. Use the relation 2 m m m GM g R ƒ to find the acceleration due to ...

precalculus - The acceleration acting on a falling object due to gravity varies ...

physics - Find the distance (measured in earth radii, RE) from the center of the...

Math - The gravitational acceleration, g, on the Earth is proportional to the ...

Math - The acceleration due to gravity is inversely proportional to the square ...

Physics help please - The space shuttle orbits at a distance of 335 km above the...

physics - If the earth acceleration due to gravity on a mass of 2000kg on the ...

Physics - A spaceship of mass m travels from the Earth to the Moon along a line ...

math - What is the acceleration due to gravity at a distance of 1.2 Earth radii...

physics - What is the acceleration due to gravity at a distance of 1.2 Earth ...