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November 22, 2014

November 22, 2014

Posted by **Math is HARD** on Tuesday, November 9, 2010 at 5:33am.

(a) At what time does the projectile attain its maximum height? Show some work.

(b) What is the maximum height attained by the projectile? Show some work.

- math -
**Damon**, Tuesday, November 9, 2010 at 6:19ams(t) = –16t^2 + 128t + 30

can do this with or without calculus

using calculus

ds/dt = -32 t + 128

= 0 at max height

32 t = 128

t = 4 seconds

for max height

s(4) = -16(16) +128(4) + 30

s(4) = 286

without calculus find vertex of parabola

16 t^2 -128 t = -s+30

complete square

t^2 - 8t = -(1/16)s + (30/16)

t^2 - 8 t + 16 = -(1/16)s + 15/8 + 16

(t-4)^2 = etc

so vertex at t = 4

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