Posted by Kelly on Tuesday, November 9, 2010 at 3:31am.
Start by grouping all the log terms together.
log2(3x-1)-log2(x-1)-log2(x+1)=0
log2[(3x-1)/(x-1)(x+1)]=0
remove the log2
[(3x-1)/(x-1)(x+1)]= 2^0 = 1
solve for x
I got x=3
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