Start by grouping all the log terms together.
remove the log2
[(3x-1)/(x-1)(x+1)]= 2^0 = 1
solve for x
I got x=3
math - solve the equation log2(x+4)-log4x=2 the 2 and 4 are lower than the g ...
math/algebra - solve the equation log2(3x-2) - log2 (x-5)=4
Logarithms - I'm working on logarithmic equations and I'm stuck on how my book ...
Math - How do you solve: log2(x-1)+log2(x-2)=1 I got up to x^2-3x=0 Is it no ...
algebra - Solve for x 1. log5 X=3 2. Log2 16-log2 =x 3. Log9 6561=x
Algebra - Solve the logarithmic equation. log2(4x)-log2(x+3)=1
Math - Logarithmic - Solve: 2^(5x-6) = 7 My work: log^(5x-6) = log7 5x - 6(log2...
Math - Can someone solve this showing the steps involved 4^log2(2^log2 5)
AP Math - Solve: log2(2x^2)[log2(16x)]= 9/2log2x
calculus - Solve the equations i) log2(x + 2) + log2 x = 3. ii) 25^x + 5^x+1 + 6...