Posted by Kelly on .
solve log2(3x1)log2(x1)=log2(x+1)
i have absolutely no idea how to solve this. can anyone help me, please?

Algebra 2 
Dr Russ,
Start by grouping all the log terms together.
log2(3x1)log2(x1)log2(x+1)=0
log2[(3x1)/(x1)(x+1)]=0
remove the log2
[(3x1)/(x1)(x+1)]= 2^0 = 1
solve for x
I got x=3