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December 19, 2014

December 19, 2014

Posted by **Kelly** on Tuesday, November 9, 2010 at 3:31am.

i have absolutely no idea how to solve this. can anyone help me, please?

- Algebra 2 -
**Dr Russ**, Tuesday, November 9, 2010 at 4:00amStart by grouping all the log terms together.

log2(3x-1)-log2(x-1)-log2(x+1)=0

log2[(3x-1)/(x-1)(x+1)]=0

remove the log2

[(3x-1)/(x-1)(x+1)]= 2^0 = 1

solve for x

I got x=3

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