How many moles of chlorine gas would reacht with 10 moles of sodium to form sodium chloride?
2Na + Cl2 ==> 2NaCl.
10 moles Na will react with 5 moles Cl2 to produce 10 moles NaCl.
To figure out how many moles of chlorine gas would react with 10 moles of sodium, we first need to look at the balanced chemical equation for the reaction between sodium and chlorine gas to form sodium chloride.
The balanced chemical equation is:
2 Na + Cl2 -> 2 NaCl
From the equation, we can see that 2 moles of sodium react with 1 mole of chlorine gas to form 2 moles of sodium chloride.
Now, let's calculate how many moles of chlorine gas would react with 10 moles of sodium:
Using the ratio from the balanced equation, we know that for every 2 moles of sodium, we need 1 mole of chlorine gas. Thus, the ratio of sodium to chlorine gas is 2:1.
Since we have 10 moles of sodium, we can set up the following ratio to find the moles of chlorine gas:
10 moles Na / 2 moles NaCl = x moles Cl2 / 1 mole NaCl
Cross-multiplying the ratios:
10 moles Na x 1 mole NaCl = 2 moles Na x x moles Cl2
10 moles NaCl = 2x moles Cl2
Dividing both sides by 2:
10 moles NaCl / 2 = 2x moles Cl2 / 2
5 moles NaCl = x moles Cl2
Therefore, 5 moles of chlorine gas would react with 10 moles of sodium to form sodium chloride.