Posted by Nancy on Monday, November 8, 2010 at 11:16pm.
This looks like a continuation of your last problem
Visualize taking a tin can apart.
you would have 2 circles, the top and the bottom
plus the sleeve that forms the can.
Pretend you are opening it up by cutting along the height of the can.
Would you not have a rectangle whose length is the circumference of the circle, and whose width is the height ?
So the total area would be
top + bottom + rectangle
= πr^2 + πr^2 + (2πr)h, where h is the height.
= 2πr^2 + (2πr)h
This is precisely what I used in the previous question.
You will need the height, or else be able to calculate it like in your previous question when the volume was given.
Thank you!!
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