Posted by **katy** on Monday, November 8, 2010 at 10:32pm.

a wheel of radius R rotates making f revolutions per second. the quantity f is know as the frecuency of the motion. show tha 1/f is the time to complete one revolution, called the period T of the motion. show that the centripetal acceleration of a point at the rim of the wheel is a=4(3.14)^2Rf^2

3.14=pi

- physics help!! -
**bobpursley**, Monday, November 8, 2010 at 10:45pm
The distance around the wheel is 2PI*r

that is the distance it goes on one rev.

so on one rev, it goes 2PI*r, now in one second, it does this f times,

so the time for one revolution then is 1/f.

centripetal acceleration= v^2/r

but v= 2PI*r/period=2PI*r*f

v^2=4PI^2 r^2 f^2

so v^2/r= 4PI^2 f^2 r

## Answer This Question

## Related Questions

- physics - a wheel of radius R rotates making f revolutions per second. the ...
- physics constant angular acceleration - A wheel with radius 25.2 cm rotates with...
- Physics - A bicycle wheel that initially spins at 3 revolutions per second is ...
- Maths - A ferris wheel has an axle standing 38m off the ground and a radius of ...
- physics - A bicycle wheel of radius 0.4 m is spinning at a rate of 40 ...
- trig - 1. A Ferris wheel with a radius of 7m makes one complete revolution every...
- physics - Leonâ€™s bicycle wheels have a circumference of 2 m. What is his linear...
- physics - Please help with these problems. Thanks! Suppose the circumference of ...
- Physics - Please help with these problems, I don't understand them. Thanks! ...
- Math - Suppose that a water wheel has a radius of 22 feet and makes a complete ...

More Related Questions