Homework Help: physics help!!

Posted by katy on Monday, November 8, 2010 at 10:32pm.

a wheel of radius R rotates making f revolutions per second. the quantity f is know as the frecuency of the motion. show tha 1/f is the time to complete one revolution, called the period T of the motion. show that the centripetal acceleration of a point at the rim of the wheel is a=4(3.14)^2Rf^2
3.14=pi

physics help!! - bobpursley, Monday, November 8, 2010 at 10:45pm
The distance around the wheel is 2PI*r

that is the distance it goes on one rev.

so on one rev, it goes 2PI*r, now in one second, it does this f times,

so the time for one revolution then is 1/f.

centripetal acceleration= v^2/r
but v= 2PI*r/period=2PI*r*f
v^2=4PI^2 r^2 f^2
so v^2/r= 4PI^2 f^2 r

Answer this Question

Related Questions

physics - a wheel of radius R rotates making f revolutions per second. the ...
physics constant angular acceleration - A wheel with radius 25.2 cm rotates with...
physics - A bicycle wheel of radius 0.4 m is spinning at a rate of 40 ...
Physics - A bicycle wheel that initially spins at 3 revolutions per second is ...
trig - A wheel rotates at 100 revolutions per second. find the angle velocity in...
physics-circular motion - the turntable of a record player rotates at a rate of ...
physics - A string is wound is tightly around a wheel. When the end of the ...
Physics - A bike wheel rotates uniformly through 2 revolutions in 3 seconds. a) ...
physics - A typical ten-pound car wheel has a moment of inertia of about 0.35 kg...
physics - A typical ten-pound car wheel has a moment of inertia of about 0.35 kg...

For Further Reading

First Name:
School Subject:
Answer: