Posted by scott on .
Suppose that a department contains 8 men and 20 women. How many ways are there to form a committee with 6 members if it must have strictly more women than men?

statistics 
Reiny,
If more women than men, possibilities are
6W, 0M
5W, 1M
4W, 2M
3W, 3M  no longer possible
6W,0M > C(20,6) x C(8,0) = 38760
5W, 1M > C(20,5) x (8,1) = 15504(8) = 124032
4W, 2M > C(20,4) x C(8,2) = 4845(28) = 135660
add them up