Sunday

December 21, 2014

December 21, 2014

Posted by **scott** on Monday, November 8, 2010 at 9:52pm.

- statistics -
**Reiny**, Monday, November 8, 2010 at 10:23pmIf more women than men, possibilities are

6W, 0M

5W, 1M

4W, 2M

3W, 3M --- no longer possible

6W,0M ---> C(20,6) x C(8,0) = 38760

5W, 1M ---> C(20,5) x (8,1) = 15504(8) = 124032

4W, 2M ---> C(20,4) x C(8,2) = 4845(28) = 135660

add them up

**Answer this Question**

**Related Questions**

math - Suppose that a department contains 11 men and 19 women. How many ways are...

Discreate Math - Suppose that a department contains 13 men and 19 women. How ...

discrete math - Suppose that a department contains 10 men and 17 women. How many...

discrete math - Suppose that a department contains 10 men and 17 women. How many...

math - A department contains 13 men and 20 women. How many ways are there to ...

math - A department contains 12 men and 17 women. How many ways are there to ...

statistics permutations and combinations - Selecting a committee: There are 7 ...

math - from a group of women and 4 men, determine in how many ways a committee ...

gr12 math - froma group of 6 ladies and 4 men, determine in how many ways a ...

maths - How can I select a committee of 5 people out of 10 men and 8 women. ...