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March 31, 2015

March 31, 2015

Posted by **scott** on Monday, November 8, 2010 at 9:52pm.

- statistics -
**Reiny**, Monday, November 8, 2010 at 10:23pmIf more women than men, possibilities are

6W, 0M

5W, 1M

4W, 2M

3W, 3M --- no longer possible

6W,0M ---> C(20,6) x C(8,0) = 38760

5W, 1M ---> C(20,5) x (8,1) = 15504(8) = 124032

4W, 2M ---> C(20,4) x C(8,2) = 4845(28) = 135660

add them up

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