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Posted by on Monday, November 8, 2010 at 9:27pm.

A satellite has a mass of 5600 kg and is in a circular orbit 3.70*10^5 m above the surface of a planet. The period of the orbit is two hours. The radius of the planet is 4.20*10^6 m. What is the true weight of the satellite when it is at rest on the planet's surface?

  • Physics - , Monday, November 8, 2010 at 10:21pm

    Inorbit?

    ForceGravity=centripetal force
    GMm/(3.7E5+4.6E6)^2=mv^2/r

    but v= 2PIr/T
    = m 4PI^2*(4.6E6+3.7E5)/T

    solve for GM

    Now, with GM known,

    weight at the surface= m*GM/(4.2E6)^2

  • Physics - , Thursday, November 11, 2010 at 11:24pm

    where did you get 4.6*10^6?

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