A satellite has a mass of 5600 kg and is in a circular orbit 3.70*10^5 m above the surface of a planet. The period of the orbit is two hours. The radius of the planet is 4.20*10^6 m. What is the true weight of the satellite when it is at rest on the planet's surface?
Physics - bobpursley, Monday, November 8, 2010 at 10:21pm
but v= 2PIr/T
= m 4PI^2*(4.6E6+3.7E5)/T
solve for GM
Now, with GM known,
weight at the surface= m*GM/(4.2E6)^2
Physics - Ashley, Thursday, November 11, 2010 at 11:24pm
where did you get 4.6*10^6?