Post a New Question


posted by .

A satellite has a mass of 5600 kg and is in a circular orbit 3.70*10^5 m above the surface of a planet. The period of the orbit is two hours. The radius of the planet is 4.20*10^6 m. What is the true weight of the satellite when it is at rest on the planet's surface?

  • Physics -


    ForceGravity=centripetal force

    but v= 2PIr/T
    = m 4PI^2*(4.6E6+3.7E5)/T

    solve for GM

    Now, with GM known,

    weight at the surface= m*GM/(4.2E6)^2

  • Physics -

    where did you get 4.6*10^6?

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question