How many H2O molecules are formed when 14 methanol molecules react?
I don't know what you're reacting it with but with a formula of CH3OH for methanol, probably not more than 1 molecule H2O/1 molecule of CH3OH or 14 H2O molecules overall.
When two molecules of methanol (CH3OH) react with oxygen, they combine with three O2 molecules to form two CO2 molecules and four H2O molecules. How many H2O molecules are formed when 14 methanol molecules react?
--I'm sure that's what you meant--
Equation:
2CH3OH + 3O2 = 2CO2 + 4H2O
Ratio used: 4 molecules of H2O for every 2 molecules of CH3OH
Answer:
14 molecule CH3OH x (4 molecule H2O)/(2 molecules CH3OH)= 28 molecules of H2O
To determine how many H2O molecules are formed when 14 methanol molecules react, we need to know the balanced chemical equation for the reaction between methanol (CH3OH) and water (H2O). Could you provide the balanced chemical equation for the reaction you are referring to?
To determine the number of H2O molecules formed when 14 methanol molecules react, we need to know the balanced chemical equation for the reaction.
The balanced equation for the reaction between methanol (CH3OH) and oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is:
2 CH3OH + 3 O2 -> 2 CO2 + 4 H2O
From this balanced equation, we can see that for every 2 molecules of methanol, we obtain 4 molecules of water.
Now, we can calculate the number of H2O molecules formed when 14 methanol molecules react:
Number of H2O molecules = (Number of methanol molecules / 2) * 4
= (14 / 2) * 4
= 7 * 4
= 28
Therefore, when 14 methanol molecules react, 28 H2O molecules are formed.