How would you solve this equation for x?

y= -4x^3+15x^2-1

collect like terms and substitute 0for y? i think im just now doing this in my senior year in middle school algebra1

are you solving

-4x^3 + 15x^2 - 1 = 0 ?
then
4x^3 - 15x^2 + 1 = 0
to solve cubics I use this webpage cubic equation calculator, since there is no easy way to do this.

http://www.1728.com/cubic.htm

It showed that x = -1/4 is a solution, so divide
4x^3 - 15x^2 + 1 by (4x+1) to reduce it down to a quadratic, then use the quadratic formula to find the other two roots.

To solve the equation y = -4x^3 + 15x^2 - 1 for x, you need to rearrange the equation so that x is isolated on one side of the equation. Here's the step-by-step process:

1. Start with the equation: y = -4x^3 + 15x^2 - 1

2. Add 1 to both sides of the equation to move the constant term to the right side: y + 1 = -4x^3 + 15x^2

3. Rearrange the terms in descending order of the exponent: -4x^3 + 15x^2 = y + 1

4. Divide both sides of the equation by the common factor, if any. In this case, there is no common factor.

5. Now you have a cubic equation in standard form: -4x^3 + 15x^2 - (y + 1) = 0

To find the values of x that satisfy the equation, you can use various methods such as factoring, synthetic division, or numerical approximation methods like Newton's method or the bisection method. The appropriate method depends on the complexity of the equation and the desired level of precision.

If you need further assistance with solving the equation using specific methods, please let me know.