Posted by Hannah on Monday, November 8, 2010 at 4:40pm.
no, not exactly.
y=x/(2x+1)
2xy+y=x
x(2y-1)=-y I skipped a step here, work it out
2xy-x=-y
x(2y-1)=-y
x=-y/(2y-1)
so the inverse function is
f'(x)=-x/(2x-1)
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