Posted by Paul on .
I conducted an experiment of the heat of combustion for three alcohol fuels, methyl, propyl and ethyl.
The results were:
mass before was 231.81g
temp of water before heating was 15 deg c.
temp of water after heating was 40 deg c.
mass of methyl after heating 229.92g
volume of water heated 112 ml
result 1481 cal/g
mass before was 183,01g
temp of water before heating was 11 deg c.
temp of water after heating was 41 deg c.
mass of methyl after heating 180.90g
volume of water heated 130 ml
result 1848 cal/g
mass before was 232.23g
temp of water before heating was 13 deg c.
temp of water after heating was 39 deg c.
mass of methyl after heating 231.08g
volume of water heated 116 ml
Result 2623 cal/g
I need to analyse my results and draw a conclusion from them can you help me please.
You've done the hard part; i.e., the calculation. I checked the first one and it's ok. I didn't check the other two.
Look at the numbers.
methyl alcohol = 1481 cal/g
ethyl alcohol = 1848 cal/g
propyl alcohol = 2623 cal/g
Per gram of alcohol, which produces more heat? Look at the cost per gram and see which is the least expensive. It would be good to put something in about the precision of your work but apparently you performed each experiment only once.