what is the area of 2 triangles whose legs are 2 feet each and touch side to side???
To find the area of the two triangles with legs measuring 2 feet each and touching side to side, you can follow these steps:
Step 1: Calculate the area of one of the triangles.
Since the legs of the triangle are both 2 feet, the base of the triangle is 2 feet. To find the height of the triangle, draw an altitude from the vertex opposite the base to the base. This altitude splits the triangle into two right triangles, with each leg measuring 2 feet. By using the Pythagorean theorem, we can find the height (h) of the triangle.
By applying the Pythagorean theorem, we have: h^2 = 2^2 - 1^2.
Solving the equation, h^2 = 3, which simplifies to h = √3.
Now that we have the base (b = 2 feet) and height (h = √3 feet), we can calculate the area of one triangle by using the formula: Area = 1/2 * base * height.
Step 2: Multiply the area of one triangle by 2.
Since there are two triangles with the same dimensions, we can simply multiply the area of one triangle by 2 to find the total area of both triangles.
Let's calculate the area using the formula:
Area = 1/2 * 2 * √3 = √3 square feet.
Finally, multiply the area of one triangle (√3 square feet) by 2 to get the total area of both triangles:
Total Area = √3 * 2 = 2√3 square feet.
Therefore, the area of the two triangles is 2√3 square feet.