What is the concentration of ammonia in a solution if 22.35mL of a 0.1145M solution of HCl are needed to titrate a 100.0mL sample of the solution?
mL x M = mL x M
To find the concentration of ammonia in the solution, we need to use the concept of stoichiometry and the balanced chemical equation for the reaction between ammonia (NH3) and hydrochloric acid (HCl).
The balanced equation is:
NH3 + HCl -> NH4Cl
From the balanced equation, we can see that one mole of ammonia reacts with one mole of hydrochloric acid to produce one mole of ammonium chloride.
First, we need to determine the number of moles of HCl used in the titration:
moles of HCl = concentration of HCl x volume of HCl
Given that the concentration of HCl is 0.1145 M and the volume of HCl used is 22.35 mL (or 0.02235 L), we can calculate the moles of HCl:
moles of HCl = 0.1145 M x 0.02235 L = 0.002558 moles
Since the reaction between HCl and NH3 is 1:1, the moles of NH3 in the solution must also be 0.002558 moles.
Next, we can determine the concentration of NH3 in the solution.
The concentration of NH3 is given by:
concentration of NH3 = moles of NH3 / volume of NH3
Given that the volume of NH3 is 100.0 mL (or 0.100 L), we can calculate the concentration of NH3:
concentration of NH3 = 0.002558 moles / 0.100 L = 0.02558 M
Therefore, the concentration of ammonia in the solution is 0.02558 M.