Posted by Amanda on Monday, November 8, 2010 at 2:34pm.
The secret to these problems is to know where you are on the titration curve.
For 10.0 mL.
moles (CH3)3N = M x L.
moles HCl = M x L.
pH = pKa + (base/acid)
At the equivalence point, the salt is present and that will hydrolyze.
(CH3)3NH^+ + H2O ==> H3O^+ + (CH3)3N
Ka = (Kw/Kb) = (H3O^+)[(CH3)3N]/([(CH3)3NH^+)]
Solve for H3O^+ and convert to pH.
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