A 1.0kg metal head of a geology hammer strikes a solid rock with a velocity of 5.0m/s. Assuming all the energy is retained by the hammer head, how much will its temperature increase?

1/2 m b^2= m*specificheatSteel*deltatemp

notice mass divide out. look up the specific heat constant, compute deltatemp

I'm still confused.....can you please show me how to set this up?

To determine the increase in temperature of the hammer head, we need to use the concept of energy conservation.

The energy gained by the hammer head can be calculated using the formula:

ΔE = m * v^2 / 2

where ΔE is the change in energy, m is the mass of the hammer head, and v is its velocity. In this case, the mass (m) is 1.0 kg and the velocity (v) is 5.0 m/s.

Substituting the values:

ΔE = 1.0 kg * (5.0 m/s)^2 / 2
ΔE = 12.5 J

The next step is to calculate the increase in temperature using the specific heat capacity of the hammer head material. The specific heat capacity (C) represents the amount of energy required to raise the temperature of a unit mass by one degree Celsius.

The formula to calculate the change in temperature (ΔT) is:

ΔT = ΔE / (m * C)

However, to proceed further, we need the specific heat capacity of the hammer head material. Different materials have different specific heat capacities, so we cannot calculate the increase in temperature without this information.

If you can provide the specific heat capacity (C) of the hammer head material, we can proceed with the calculation.