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November 28, 2014

November 28, 2014

Posted by **help** on Monday, November 8, 2010 at 1:22am.

- 11th grade physics -
**Anonymous**, Friday, October 12, 2012 at 1:59pmLet 'x' be the angle of projectile with the horizontal.

Then,taking g=10m/s^2:

Given, Hmax=[(usinx)^2]/2g;

R=4(root of 3)x(Hmax);

R=[(u^2)(sin2x)]/g;

Thus,

(u^2)sin2x 4(usinx)^2

-------- = --------------

g (root of 3)2g

Then,upon simplification:

sin2x 2(sinx)(sinx)

----- = -------------

1 (root of 3)

2sinxcosx 2

--------- = -----------

sinxsinx (root of 3)

cosx 1

---- = cotx = -----------

sinx (root of 3)

So,x=60 degrees.

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