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March 27, 2017

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the horizontal range of a projectile is 4 root 3 times of its maximum height. calculate the angle of projection.

  • 11th grade physics - ,

    Let 'x' be the angle of projectile with the horizontal.
    Then,taking g=10m/s^2:

    Given, Hmax=[(usinx)^2]/2g;
    R=4(root of 3)x(Hmax);
    R=[(u^2)(sin2x)]/g;
    Thus,
    (u^2)sin2x 4(usinx)^2
    -------- = --------------
    g (root of 3)2g
    Then,upon simplification:
    sin2x 2(sinx)(sinx)
    ----- = -------------
    1 (root of 3)

    2sinxcosx 2
    --------- = -----------
    sinxsinx (root of 3)

    cosx 1
    ---- = cotx = -----------
    sinx (root of 3)

    So,x=60 degrees.

  • 11th grade physics - ,

    It is not correct book answer

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