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March 28, 2017

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A rectangular block of ice 10 m on each side and 1.1 m thick floats in sea water. The density of the sea water is 1025 kg/m3. The density of ice is 917 kg/m3.


a) How high does the top of the ice block float above the water level?

m *
.116 OK

HELP: Use Archimedes' Priciple.

b) How many penguins of mass 27 kg each can stand on the ice block before they get their feet wet?


4 NO

HELP: Their feet will get wet if the ice block sinks below the water surface.

Just need b

  • physics - ,

    total volume of ice = 100*1.1 = 110m^3
    mass of ice = 917*110 = 100870 kg
    that is the mass of water displaced (Archimedes)
    so
    volume of water displaced = 100870/1025
    =98.41m^3
    so
    100m^2 * x = 98.41 where x is the draft
    x = .984 m
    so height out of water = 1.1-.984 = .116m
    added mass of penguins = 27 n
    mass of water displaced by penquin mass = 1025*100*.116
    so
    27 n = 1025*100*.116
    n = 440

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