Posted by Jessica on Sunday, November 7, 2010 at 11:40pm.
3,4,5 triangle
Vertical forces
200 N down at middle, 1.5 m from foot of ladder
700 N down at (3x/5) from foot of ladder
900 N up at foot of ladder
Horizontal forces
F at top of ladder, 4 m above base
900 mu at base of ladder = F at top
take moments about
base of ladder
700 (3x/5) + 200(1.5) - 4F = 0
but F = .5*900 = 450
so
700(3x/5) +300 = 1800
420 x = 1500
x = 3.57
what about the friction?
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