what is the percentage of hydrogen in calcium acetate?
molar mass Ca(C2H3O2)2 = ??
mass H in compound is 6
%H = (6/molar mass compound)*100 = ??
To determine the percentage of hydrogen in calcium acetate, we first need to know the chemical formula for calcium acetate. The chemical formula for calcium acetate is Ca(C₂H₃O₂)₂.
To find the percentage of hydrogen, we need to calculate the molar mass of hydrogen in calcium acetate and divide it by the molar mass of the compound, then multiply by 100.
The molar mass of hydrogen (H) is approximately 1.01 g/mol. The molar mass of calcium (Ca) is approximately 40.08 g/mol, and the molar mass of acetate (C₂H₃O₂) is approximately 59.04 g/mol (2 * 12.01 g/mol for carbon, 3 * 1.01 g/mol for hydrogen, and 2 * 16.00 g/mol for oxygen).
Now, let's calculate the molar mass of calcium acetate:
Molar mass of Ca = 40.08 g/mol
Molar mass of 2 * C = 2 * 12.01 g/mol = 24.02 g/mol
Molar mass of 3 * H = 3 * 1.01 g/mol = 3.03 g/mol
Molar mass of 4 * O = 4 * 16.00 g/mol = 64.00 g/mol
Total molar mass of calcium acetate = 40.08 g/mol + 24.02 g/mol + 3.03 g/mol + 64.00 g/mol = 131.13 g/mol
Now, let's determine the percentage of hydrogen in calcium acetate:
Percentage of hydrogen = (molar mass of hydrogen / molar mass of calcium acetate) * 100
Percentage of hydrogen = (3.03 g/mol / 131.13 g/mol) * 100 = 2.32%
Therefore, the percentage of hydrogen in calcium acetate is approximately 2.32%.
To determine the percentage of hydrogen in calcium acetate, we need to know the chemical formula of calcium acetate. Calcium acetate has the molecular formula Ca(CH3COO)2.
To find the percentage of hydrogen, we need to calculate the molar mass of hydrogen and the molar mass of the entire compound.
The molar mass of hydrogen (H) is approximately 1 gram per mole (g/mol).
The molar mass of calcium acetate (Ca(CH3COO)2) can be calculated by summing the molar masses of all the atoms in the formula.
- The molar mass of calcium (Ca) is approximately 40 g/mol.
- The molar mass of carbon (C) is approximately 12 g/mol.
- The molar mass of oxygen (O) is approximately 16 g/mol.
- The molar mass of hydrogen (H) is approximately 1 g/mol.
Now, let's calculate the molar mass of calcium acetate:
(1 atom of calcium)*(40 g/mol) + (4 atoms of carbon)*(12 g/mol) + (6 atoms of hydrogen)*(1 g/mol) + (4 atoms of oxygen)*(16 g/mol) + (2 atoms of oxygen)*(16 g/mol) = 158 g/mol
To calculate the percentage of hydrogen in calcium acetate, we divide the molar mass contribution of hydrogen (6 g/mol) by the total molar mass of calcium acetate (158 g/mol) and multiply it by 100:
(6 g/mol / 158 g/mol) * 100 = 3.8%
Therefore, the percentage of hydrogen in calcium acetate is approximately 3.8%.