Friday

January 30, 2015

January 30, 2015

Posted by **Aileen** on Sunday, November 7, 2010 at 9:22pm.

There is an 18 kg box on a 32degree incline. a HORIZONTAL force of 150 N is given to the box

a) How much work is done by the horizontal force F = 150 N on the 18-kg block of the figure when the force pushes the block 5.1 m up along the 32degree incline? ľk = 0.13.

ANSWER: 650 J

b) How much work is done by the gravitational force on the block during this displacement? -480 J

c) How much work is done by the normal force? 0J

d) What is the speed of the block (assume that it is zero initially) after this displacement?

I tried adding up (Fpcostheta - mgcostheta -Ffriction) but it doesn't work

thank you!!

- physics -
**Brian**, Tuesday, November 9, 2010 at 7:49pmUse the work-energy principle:

Wnet=1/2mv^2-1/2mv^2

Initial velocity is zero therefore:

Wnet=1/2mv^2

Ans: 4.3 m/s

**Answer this Question**

**Related Questions**

Pre-Calc - Convert Q = 2e^8t to form Q = ab^t Round all calculated values to ...

Chemistry - What are intermolecular forces? What do intermolecular forces have ...

To DrBob222 - Can you please explain thoroughly to me about all this. Why do we ...

factoring cubes - how to factor x^3-27 well since 27 is a perfect cube and so is...

calculus - functions! - I was assigned this problem and I'm coming up against a ...

Math Integration - i keep getting stuck and i think im missing something ...

physics - k so question is one you have all answered previously, 3 different ...

physics - When a large bone such as the femur is broken, the two pieces are ...

Physics - Physics question on identify the reaction? I am having trouble with ...

Physics - A car is going 20m/s when they see a traffic light 200m ahead turn red...