At 3 pm a plane left the airport for LA traveling at 600 mph. At 3:30, another plane left the same airport on the same route traveling 650 mph. What time did the 2nd plane overtake the first.
A. 5:15 pm
B. 6:45 pm
C. 6:50 pm
D: 7:15 pm
E: 9:30 pm
Is D correct?
I think so
E option is correct because
9:30 - 3:00 = 6:30 or 6.5
By applying rt= S
6.5 * 600 = 3900miles
9:30 -3:30 = 6:00 or 6
By applying rt= s
6 * 650 = 3900miles
To determine the time when the second plane overtakes the first, we need to find the time it takes for the second plane to cover the distance between them.
First, let's calculate the time it takes for the first plane to travel from 3 pm to the point of intersection. Since it travels at a speed of 600 mph, and the second plane departs at 3:30 pm, the first plane has a 30-minute head start. Therefore, the time for the first plane to the point of intersection is:
Distance = Speed × Time
Time = Distance / Speed
Time = 600 * (3:30 - 3) = 600 * 0.5 = 300 miles
Now, we can determine the time it takes for the second plane to cover this distance. Since it travels at a speed of 650 mph, the time it takes is:
Time = Distance / Speed
Time = 300 / 650 ≈ 0.4615 hours ≈ 27.7 minutes
Adding this time to the departure time of the second plane (3:30 pm), we can find the time when the second plane overtakes the first.
3:30 pm + 00:27.7 = 3:57.7 pm
Therefore, the second plane overtakes the first plane at approximately 3:57.7 pm, which can be rounded to 4:00 pm.
None of the given options exactly match this time.
To find the time when the second plane overtakes the first plane, we need to calculate the time it takes for the second plane to catch up to the first plane.
Let's consider the time it takes for the second plane to catch up to the first plane after it takes off at 3:30 pm.
From 3:30 pm to the time they meet, both planes will be flying for the same amount of time. Let's call this time "t" hours.
For the first plane, which leaves at 3 pm and travels at 600 mph, the distance it travels in "t" hours is 600t miles.
For the second plane, which leaves at 3:30 pm and travels at 650 mph, the distance it travels in "t" hours is 650t miles.
Since both planes meet each other, their distances traveled should be the same. Therefore, we can set up the equation:
600t = 650t
Now we can solve for "t":
600t - 650t = 0
-50t = 0
t = 0
However, this solution doesn't make sense in the context of our problem since it means the planes meet instantaneously, which is not possible.
Therefore, there seems to be an error in the problem statement, or the options provided do not include the correct answer.
Without further information, we cannot accurately determine the time when the second plane overtakes the first plane.