A HIKER SHOUTS TOWARD A VERTICAL CLIFF 685 M AWAY. THE ECHO IS HEARD 4.00 SECONDS LATER.
WHAT IS THE SPEED OF SOUND OF THE HIKER'S VOICE IN AIR?
well,the sound traveled 2*685m
totaldistance= velocitysound*timetotal
To determine the speed of sound of the hiker's voice in air, we can use the formula:
Speed of Sound = Distance / Time
Given that the distance to the cliff is 685 m and the time it takes for the echo to be heard is 4.00 seconds, we can substitute these values into the formula:
Speed of Sound = 685 m / 4.00 s
Simplifying the calculation,
Speed of Sound = 171.25 m/s
Therefore, the speed of sound of the hiker's voice in air is approximately 171.25 m/s.
To find the speed of sound of the hiker's voice in the air, we need to use the formula:
Speed = Distance / Time
In this case, the distance is twice the distance to the cliff because the sound wave has to travel from the hiker to the cliff and then back to the hiker (round trip). So the total distance is 2 * 685 m = 1370 m.
The time it takes for the sound wave to travel this distance is given as 4.00 seconds.
Plugging these values into the formula, we have:
Speed = 1370 m / 4.00 s
Now, let's calculate the speed:
Speed = 342.5 m/s
Therefore, the speed of sound of the hiker's voice in air is 342.5 m/s.