The two forces F1 and F2 act on a 27-kg object on a frictionless tabletop. If F1 = 7.1 N and F2 = 33 N, find the net force on the object and its acceleration.

WHAT IN the world...how do i figure this out!

The direction of the forces is important.

F2 is straight up at a 90 degree angle to the x axis, and F1 and F2 form an 120 degree angle

To find the net force on the object, you need to add the two forces together. The net force is the vector sum of all the individual forces acting on the object. In this case, you can add F1 and F2 to find the net force.

Net force (Fnet) = F1 + F2

Substituting the given values:
Fnet = 7.1 N + 33 N

Now, calculate the net force:
Fnet = 40.1 N

The net force acting on the object is 40.1 N.

To find the acceleration of the object, you can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The equation is:

Fnet = m * a

Where Fnet is the net force, m is the mass of the object, and a is its acceleration.

Substituting the given values:
40.1 N = 27 kg * a

Now, solve for the acceleration:
a = 40.1 N / 27 kg

Calculating the acceleration:
a ≈ 1.48 m/s^2

The net force acting on the object is 40.1 N, and its acceleration is approximately 1.48 m/s^2.

To find the net force on the object and its acceleration, you can use Newton's second law of motion: F(net) = m * a, where F(net) is the net force, m is the mass of the object, and a is the acceleration.

1. Start by finding the net force (F(net)). To do this, simply add the two forces acting on the object together:
F(net) = F1 + F2

In this case, F1 = 7.1 N and F2 = 33 N:
F(net) = 7.1 N + 33 N
= 40.1 N

Therefore, the net force on the object is 40.1 N.

2. Now, to find the acceleration (a), rearrange the equation F(net) = m * a to solve for a:
a = F(net) / m

In this case, the mass (m) of the object is given as 27 kg and the net force (F(net)) is 40.1 N:
a = 40.1 N / 27 kg
≈ 1.48 m/s²

Therefore, the acceleration of the object is approximately 1.48 m/s².

So, the net force on the object is 40.1 N and its acceleration is approximately 1.48 m/s².