Questions Math
A bag contains four balls. Three are red, and the fourth is either red or blue, selected with equal probability. A ball is drawn from the ball and it is red. What is the probability that one of the balls still in the bag is blue?
It all hinges on the probability of the fourth ball, which can either be red or blue, .5.
answered by
PsyDAG
13 years ago
0
0
You can ask a new question or answer this question .
Similar Questions
Rewrite: Consider a bag containing an unknown number of red and blue balls. Let the number of red balls in the bag be denoted as
Top answer:
To find the probability of drawing a red ball from the bag, we need to use the concept of a Poisson
Read more.
selection of colored balls from two bags. Assume that each bag contains 4 balls. Bag a contains 2 red and 2 white, while bag b
Top answer:
To solve these questions, we can use basic principles of probability. (1) To find the probability
Read more.
Top answer:
AAAaannndd the bot gets it wrong yet again! 2 each of blue and white, so P(w|r) = P(b|r) = (6+2)/10
Read more.
Top answer:
(a) P(white or red) = P(white) + P(red) = 6/10 + 6/10 = 12/10 = 6/5 (b) P(not red) = P(white) +
Read more.
Top answer:
there are 3 blue balls out of 9 there are 9-5 balls which are not red ...
Read more.
Top answer:
To find the percentage of blue balls, we first need to find the total number of balls in the bag.
Read more.
Top answer:
Red is the hardest to get, since there are only 20 of them. To make sure you get <i>some</i> red,
Read more.
Top answer:
original red --- 3x original blue --- 7x number of reds added -- a number of blues added -- 10-a
Read more.
Top answer:
There are only 3 colors. So, after 6 draws, it is possible to have two of each color. The 7th ball
Read more.