Posted by Anonymous on Sunday, November 7, 2010 at 2:22pm.
Here is a general solution:
Resultant= 300Cos25i + 300Sin25j+275Cos160i+275Sin160j+ 325Cos300i + 325Sin300j
where i is the axis angles are measured from.
Do the math above, then resultant force is the remainder.
F1 = 300 N @ 25 deg., F2 = 275 N @ 160
deg, F3 = 325 N @ 300 deg.
X = hor.=300cos25+275cos160+325cos300,
X = hor.= 271.9 + (- 258.4) + 162.5,
X = hor.= 176 N.
Y=ver.=300sin25 + 275sin160+ 325sin300
Y = ver. = 126.8 + 94.1 + (-281.5),
Y = ver. = -60.6 N.
tanA = Y/X = -60.6 / 176 = -0.3443,
A = -19.0 deg. = 341 deg. CCW.
R = X / cos341 = 176 / cos341 = 186.1 N @ 341 deg. = Resultant.
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